Mathematics · 2019
JEE Main · 9 April 2019, Shift 2 · Q76
The area (in sq. units) of the region A ={(x, y): y^2/2 ≤ x ≤ y+4} is:
The area (in sq. units) of the region
$\displaystyle \mathrm{A}=\left\{(x, y): \frac{y^2}{2} \leq x \leq y+4\right\}$ is :
Official answer
(1)
$\displaystyle 18$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.