Mathematics · 2024
JEE Main · 1 February 2024, Shift 1 · Q9
The area enclosed by the curves x y+4 y=16 and x+y=6 is equal to:
The area enclosed by the curves $\displaystyle x y+4 y=16$ and $\displaystyle x+y=6$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 30-32 \log _{\mathrm{e}} 2$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.