Mathematics · 2021
JEE Main · 4 August 2021, Shift 1 · Q67
lim_x → 2(x^3-x^2-8 x+13)^(1/(x^3-3 x^2+4))
$$\lim _{x \rightarrow 2}\left(x^3-x^2-8 x+13\right)^{\frac{1}{x^3-3 x^2+4}}
$$
Official answer
(3)
exists and it is equal to $\displaystyle e^{5 / 3}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.