Mathematics · 2023
JEE Main · 11 April 2023, Shift 1 · Q7
Let f(x)=[x^2-x]+|-x+[x]|, where x ∈ R and [t] denotes the greatest integer less than or equal to t. Then, f is
Let $\displaystyle f(x)=\left[x^2-x\right]+|-x+[x]|$, where $\displaystyle x \in \mathbb{R}$ and $\displaystyle [t]$ denotes the greatest integer less than or equal to $\displaystyle t$. Then, $\displaystyle f$ is
Official answer
From NTA’s final answer key for this paper.
(4)
continuous at $\displaystyle x=1$, but not continuous at $\displaystyle x=0$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.