Let f and g be two functions defined by f(x)={ x+1, x<0; |x-1|, x ≥ 0 and g(x)= {x+1, x<0; 1, x ≥ 0}. Then (g ° f)(x) is

Let $\displaystyle f$ and g be two functions defined by $$f(x)=\left\{\begin{array}{cc} x+1, & x<0 \\ |x-1|, & x \geq 0 \end{array} \text { and } g(x)=\left\{\begin{array}{cc} x+1, & x<0 \\ 1, & x \geq 0 \end{array}\right.\right. $$ Then $\displaystyle (g \circ f)(x)$ is