Mathematics · 2019
JEE Main · 11 January 2019, Shift 1 · Q63
Let (-2-1/3 i)^3=(x+i y)/27(i=√ -1 ), where x and y are real numbers, then y-x equals:
Let $\displaystyle \left(-2-\frac{1}{3} i\right)^3=\frac{x+i y}{27}(i=\sqrt{-1})$, where $\displaystyle x$ and $\displaystyle y$ are real numbers, then $\displaystyle y-x$ equals :
Official answer
(1)
$\displaystyle 91$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.