Mathematics · 2021
JEE Main · 27 August 2021, Shift 1 · Q71
Let us consider a curve, y=f(x) passing through the point ( -2,2 ) and the slope of the tangent to the curve at any point (x, f(x)) is given by…
Let us consider a curve, $\displaystyle y=f(x)$ passing through the point ( $\displaystyle -2,2$ ) and the slope of the tangent to the curve at any point $\displaystyle (x, f(x))$ is given by $\displaystyle f(x)+x f^{\prime}(x)=x^2$. Then :
Official answer
(1)
$\displaystyle x^3-3 x f(x)-4=0$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.