Mathematics · 2023
JEE Main · 13 April 2023, Shift 2 · Q2
Let S={z ∈ C: z̄=i(z^2+ Re (z̄))}. Then Σ_z ∈ S |z|^2 is equal to
Let $\displaystyle S=\left\{z \in \mathbb{C}: \bar{z}=i\left(z^2+\operatorname{Re}(\bar{z})\right)\right\}$. Then $\displaystyle \sum_{z \in \mathrm{~S}}|z|^2$ is equal to
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 4$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.