Mathematics · 2023
JEE Main · 31 January 2023, Shift 1 · Q67
Let y=f(x)= sin^3((π)/3( cos ((π)/(3 √ 2)(-4 x^3+5 x^2+1)^(3/2)))). Then, at x=1,
Let $\displaystyle y=f(x)=\sin ^3\left(\frac{\pi}{3}\left(\cos \left(\frac{\pi}{3 \sqrt{2}}\left(-4 x^3+5 x^2+1\right)^{\frac{3}{2}}\right)\right)\right)$. Then, at $\displaystyle x=1$,
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 2 y^{\prime}+3 \pi^2 y=0$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.