Mathematics · 2023
JEE Main · 24 January 2023, Shift 1 · Q73
Let f(x)= {x^2 sin (1/x), x ≠ 0; 0, x=0} Then at x=0
Let $\displaystyle f(x)=\left\{\begin{array}{cc}x^2 \sin \left(\frac{1}{x}\right), & x \neq 0 \\ 0, & x=0\end{array}\right.$Then at $\displaystyle x=0$
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle f$ is continuous but $\displaystyle f^{\prime}$ is not continuous
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.