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Mathematics · 2023

JEE Main · 25 January 2023, Shift 2 · Q69

If the function f(x)= {(1+| cos x|) (λ)/(| cos x|), 0<x<(π)/2; μ, x=(π)/2; (cot 6 x)/(e^cot 4 x), (π)/2<x<π} is continuous at x=(π)/2, then 9 λ+6…

If the function $\displaystyle f(x)=\left\{\begin{array}{cll}(1+|\cos x|) \frac{\lambda}{|\cos x|} & , & 0<x<\frac{\pi}{2} \\ \mu & , & x=\frac{\pi}{2} \\ \frac{\cot 6 x}{e^{\cot 4 x}} & , & \frac{\pi}{2}<x<\pi\end{array}\right.$ is continuous at $\displaystyle x=\frac{\pi}{2}$, then $\displaystyle 9 \lambda+6 \log _{\mathrm{e}} \mu+\mu^6-\mathrm{e}^{6 \lambda}$ is equal to
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.