Mathematics · 2023
JEE Main · 10 April 2023, Shift 2 · Q7
Let the number (22)^2022+(2022)^22 leave the remainder α when divided by 3 and β when divided by 7. Then (α^2+β^2) is equal to
Let the number $\displaystyle (22)^{2022}+(2022)^{22}$ leave the remainder $\displaystyle \alpha$ when divided by $\displaystyle 3$ and $\displaystyle \beta$ when divided by $\displaystyle 7$ . Then $\displaystyle \left(\alpha^2+\beta^2\right)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 5$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.