Let the minimum value v_0 of v=|z|^2+|z-3|^2+|z-6 i|^2, z ∈ C is attained at z=z_0. Then |2 z_0^2-z̄_0^3+3|^2+v_0^2 is equal to

Let the minimum value $\displaystyle v_0$ of $\displaystyle v=|z|^2+|z-3|^2+|z-6 i|^2, z \in \mathbb{C}$ is attained at $\displaystyle z=z_0$. Then $\displaystyle \left|2 z_0^2-\bar{z}_0^3+3\right|^2+v_0^2$ is equal to