Let the mean of the data be 5. If m and σ^2 are respectively the mean deviation about the mean and the variance of the data, then (3 α)/(m+σ^2) is…

Let the mean of the data

$\displaystyle x$	$\displaystyle 1$	$\displaystyle 3$	$\displaystyle 5$	$\displaystyle 7$	$\displaystyle 9$
Frequency (f)	$\displaystyle 4$	$\displaystyle 24$	$\displaystyle 28$	$\displaystyle \alpha$	$\displaystyle 8$

be $\displaystyle 5$ . If $\displaystyle m$ and $\displaystyle \sigma^2$ are respectively the mean deviation about the mean and the variance of the data, then $\displaystyle \frac{3 \alpha}{m+\sigma^2}$ is equal to $\displaystyle \_\_\_\_$.