Mathematics · 2022
JEE Main · 27 June 2022, Shift 2 · Q13
Let the foot of the perpendicular from the point (1,2,4) on the line (x+2)/4=(y-1)/2=(z+1)/3 be P. Then the distance of P from the plane 3 x+4 y+12…
Let the foot of the perpendicular from the point $\displaystyle (1,2,4)$ on the line $\displaystyle \frac{x+2}{4}=\frac{y-1}{2}=\frac{z+1}{3}$ be $\displaystyle P$. Then the distance of $\displaystyle P$ from the plane $\displaystyle 3 x+4 y+12 z+23=0$ is
Official answer
(1)
$\displaystyle 5$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.