Mathematics · 2024
JEE Main · 6 April 2024, Shift 1 · Q12
Let the area of the region enclosed by the curves y=3 x, 2 y=27-3 x and y=3 x-x √ x be A. Then 10 A is equal to
Let the area of the region enclosed by the curves $\displaystyle y=3 x, 2 y=27-3 x$ and $\displaystyle y=3 x-x \sqrt{x}$ be $\displaystyle A$. Then $\displaystyle 10 A$ is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 162$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.