Mathematics · 2024
JEE Main · 1 February 2024, Shift 2 · Q6
Let m and n be the coefficients of seventh and thirteenth terms respectively in the expansion of (1/3 x^(1/3)+1/(2 x^(2/3)))^18. Then (n/m)^(1/3) is:
Let m and n be the coefficients of seventh and thirteenth terms respectively in the expansion of $\displaystyle \left(\frac{1}{3} x^{\frac{1}{3}}+\frac{1}{2 x^{\frac{2}{3}}}\right)^{18}$. Then $\displaystyle \left(\frac{\mathrm{n}}{\mathrm{m}}\right)^{\frac{1}{3}}$ is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{9}{4}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.