Mathematics · 2019
JEE Main · 9 January 2019, Shift 1 · Q62
Let A={θ ∈(-(π)/2, π): (3+2 i sin θ)/(1-2 i sin θ). is purely imaginary }. Then the sum of the elements in A is:
Let $\displaystyle A=\left\{\theta \in\left(-\frac{\pi}{2}, \pi\right): \frac{3+2 i \sin \theta}{1-2 i \sin \theta}\right.$ is
purely imaginary $\displaystyle \}$. Then the sum of the
elements in A is :
Official answer
(2)
$\displaystyle \frac{2 \pi}{3}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.