SolveItJEE Main
Mathematics · 2024

JEE Main · 5 April 2024, Shift 2 · Q11

Let β( m, n )=∫_0^1 x^m -1 (1-x)^n -1 d x, m, n >0. If ∫_0^1(1-x^10)^20 d x= a × β( b, c ), then 100( a + b + c ) equals ____.

Let $\displaystyle \beta(\mathrm{m}, \mathrm{n})=\int_0^1 x^{\mathrm{m}-1}(1-x)^{\mathrm{n}-1} \mathrm{~d} x, \mathrm{~m}, \mathrm{n}>0$. If $\displaystyle \int_0^1\left(1-x^{10}\right)^{20} \mathrm{~d} x=\mathrm{a} \times \beta(\mathrm{b}, \mathrm{c})$, then $\displaystyle 100(\mathrm{a}+\mathrm{b}+\mathrm{c})$ equals $\displaystyle \_\_\_\_$.
ShareWhatsAppTelegram

More from Definite Integration

JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.