Mathematics · 2020
JEE Main · 8 January 2020, Shift 2 · Q52
Let α=(-1+i √ 3)/2. If a =(1+α) Σ_k =0^100 α^2 k and b =Σ_k =0^100 α^3 k, then a and b are the roots of the quadratic equation:
Let $\displaystyle \alpha=\frac{-1+i \sqrt{3}}{2}$. If
$\displaystyle \mathrm{a}=(1+\alpha) \sum_{\mathrm{k}=0}^{100} \alpha^{2 \mathrm{k}}$ and $\displaystyle \mathrm{b}=\sum_{\mathrm{k}=0}^{100} \alpha^{3 \mathrm{k}}$, then
a and b are the roots of the quadratic equation :
Official answer
(4)
$\displaystyle x^2-102 x+101=0$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.