Mathematics · 2019
JEE Main · 11 January 2019, Shift 1 · Q70
Let [x] denote the greatest integer less than or equal to x. Then: lim_x → 0 (tan (π sin^2 x)+(|x|- sin (x[x]))^2)/x^2:
Let $\displaystyle [x]$ denote the greatest integer less than or equal to $\displaystyle x$. Then :
$$\lim _{x \rightarrow 0} \frac{\tan \left(\pi \sin ^2 x\right)+(|x|-\sin (x[x]))^2}{x^2}:
$$
Official answer
(4)
does not exist
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.