Mathematics · 2022
JEE Main · 29 June 2022, Shift 1 · Q23
Let d be the distance between the foot of perpendiculars of the points P (1,2,-1) and Q (2,-1,3) on the plane -x+y+z=1. Then d^2 is equal to \ \ \ \.
Let d be the distance between the foot of perpendiculars of the points $\displaystyle \mathrm{P}(1,2,-1)$ and $\displaystyle \mathrm{Q}(2,-1,3)$ on the plane $\displaystyle -x+y+z=1$. Then $\displaystyle \mathrm{d}^2$ is equal to \_\_\_\_.
Official answer
26
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.