Mathematics · 2025
JEE Main · 7 April 2025, Shift 2 · Q6
Let a_n be the n^th term of an A.P. If S_n = a_1+ a_2+ a_3+…+ a_n =700, a_6=7 and S_7=7, then a_n is equal to:
Let $\displaystyle \mathrm{a}_{\mathrm{n}}$ be the $\displaystyle \mathrm{n}^{\text {th }}$ term of an A.P. If $\displaystyle \mathrm{S}_{\mathrm{n}}=\mathrm{a}_1+\mathrm{a}_2+\mathrm{a}_3+\ldots+\mathrm{a}_{\mathrm{n}}=700, \mathrm{a}_6=7$ and $\displaystyle \mathrm{S}_7=7$, then $\displaystyle \mathrm{a}_{\mathrm{n}}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 64$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.