If 1/1^4+1/2^4+1/3^4+… ∞=(π^4)/90, 1/1^4+1/3^4+1/5^4+… ∞=α, 1/2^4+1/4^4+1/6^4+… ∞=β, then (α)/(β) is equal to

If $\displaystyle \frac{1}{1^4}+\frac{1}{2^4}+\frac{1}{3^4}+\ldots \infty=\frac{\pi^4}{90}$, $\displaystyle \frac{1}{1^4}+\frac{1}{3^4}+\frac{1}{5^4}+\ldots \infty=\alpha$, $\displaystyle \frac{1}{2^4}+\frac{1}{4^4}+\frac{1}{6^4}+\ldots \infty=\beta$, then $\displaystyle \frac{\alpha}{\beta}$ is equal to