Mathematics · 2021
JEE Main · 25 July 2021, Shift 2 · Q67
Let y=y(x) be the solution of the differential equation x d y=(y+x^3 cos x) d x with y(π)=0, then y((π)/2) is equal to:
Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle x \mathrm{~d} y=\left(y+x^3 \cos x\right) \mathrm{d} x$ with $\displaystyle y(\pi)=0$, then $\displaystyle y\left(\frac{\pi}{2}\right)$ is equal to :
Official answer
(4)
$\displaystyle \frac{\pi^2}{4}+\frac{\pi}{2}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.