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Mathematics · 2021

JEE Main · 18 March 2021, Shift 2 · Q69

Let y=y(x) be the solution of the differential equation (d y)/(d x)=(y+1)((y+1) e^x^2 / 2-x), 0<x<2.1, with y(2)=0. Then the value of (d y)/(d x) at…

Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}=(y+1)\left((y+1) \mathrm{e}^{x^2 / 2}-x\right)$, $\displaystyle 0<x<2.1$, with $\displaystyle y(2)=0$. Then the value of $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}$ at $\displaystyle x=1$ is equal to:
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