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Mathematics · 2022

JEE Main · 28 June 2022, Shift 1 · Q11

Let y=y(x) be the solution of the differential equation x(1-x^2) (d y)/(d x)+(3 x^2 y-y-4 x^3)=0, x>1, with y(2)=-2. Then y(3) is equal to

Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle x\left(1-x^2\right) \frac{d y}{d x}+\left(3 x^2 y-y-4 x^3\right)=0, x>1$, with $\displaystyle y(2)=-2$. Then $\displaystyle y(3)$ is equal to
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