Mathematics · 2025
JEE Main · 7 April 2025, Shift 2 · Q19
Let y=y(x) be the solution of the differential equation (x^2+1) y^′-2 x y=(x^4+2 x^2+1) cos x, y(0)=1. Then ∫_-3^3 y(x) d x is:
Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle \left(x^2+1\right) y^{\prime}-2 x y=\left(x^4+2 x^2+1\right) \cos x$, $\displaystyle y(0)=1$. Then $\displaystyle \int_{-3}^3 y(x) \mathrm{d} x$ is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 24$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.