Mathematics · 2025
JEE Main · 7 April 2025, Shift 1 · Q20
Let y=y(x) be the solution curve of the differential equation x(x^2+e^x) d y+( e^x(x-2) y-x^3) d x=0, x>0, passing through the point (1,0). Then y(2)…
Let $\displaystyle y=y(x)$ be the solution curve of the differential equation $\displaystyle x\left(x^2+e^x\right) d y+\left(\mathrm{e}^x(x-2) y-x^3\right) \mathrm{d} x=0, x>0$, passing through the point $\displaystyle (1,0)$. Then $\displaystyle y(2)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{4}{4+e^2}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.