Mathematics · 2026
JEE Main · 21 January 2026, Shift 2 · Q19
Let y=y(x) be the solution of the differential equation sec x (d y)/(d x)-2 y=2+3 sin x, x ∈(-(π)/2, (π)/2), y(0)=-7/4. Then y((π)/6) is equal to:
Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle \sec x \frac{\mathrm{~d} y}{\mathrm{~d} x}-2 y=2+3 \sin x, x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$, $\displaystyle y(0)=-\frac{7}{4}$. Then $\displaystyle y\left(\frac{\pi}{6}\right)$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle -\frac{5}{2}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.