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Mathematics · 2026

JEE Main · 4 April 2026, Shift 2 · Q25

Let f be a twice differentiable function such that f(x)=∫_0^x tan (t-x) d t-∫_0^x f(t) tan t d t, x ∈(-(π)/2, (π)/2). Then f^′ ′((π)/6)+12…

Let $\displaystyle f$ be a twice differentiable function such that $$f(x)=\int_0^x \tan (t-x) d t-\int_0^x f(t) \tan t d t, x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right). $$ Then $\displaystyle f^{\prime \prime}\left(\frac{\pi}{6}\right)+12 f^{\prime}\left(-\frac{\pi}{6}\right)+f\left(\frac{\pi}{6}\right)$ is equal to $\displaystyle \_\_\_\_$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.