Let y=y(x) be the solution curve of the differential equation sin (2 x^2) log_e( tan x^2) d y+(4 x y-4 √ 2 x sin (x^2-(π)/4)) d x=0,0<x<√((π)/2),…

Let $\displaystyle y=y(x)$ be the solution curve of the differential equation $$\sin \left(2 x^2\right) \log _e\left(\tan x^2\right) d y+\left(4 x y-4 \sqrt{2} x \sin \left(x^2-\frac{\pi}{4}\right)\right) d x=0,0<x<\sqrt{\frac{\pi}{2}}, $$ which passes through the point $\displaystyle \left(\sqrt{\frac{\pi}{6}}, 1\right)$. Then $\displaystyle \left|y\left(\sqrt{\frac{\pi}{3}}\right)\right|$ is equal to \_\_\_\_.