Let μ be the mean and σ be the standard deviation of the distribution where Σ f_i=62. If [x] denotes the greatest integer ≤ x, then [μ^2+σ^2] is…

Let $\displaystyle \mu$ be the mean and $\displaystyle \sigma$ be the standard deviation of the distribution

$\displaystyle x_i$	$\displaystyle 0$	$\displaystyle 1$	$\displaystyle 2$	$\displaystyle 3$	$\displaystyle 4$	$\displaystyle 5$
$\displaystyle f_i$	$\displaystyle \mathrm{k}+2$	2k	$\displaystyle \mathrm{k}^2-1$	$\displaystyle \mathrm{k}^2-1$	$\displaystyle \mathrm{k}^2+1$	k - $\displaystyle 3$

where $\displaystyle \sum f_i=62$. If $\displaystyle [x]$ denotes the greatest integer $\displaystyle \leq x$, then $\displaystyle \left[\mu^2+\sigma^2\right]$ is equal to