Let Q ( a, b, c ) be the image of the point P (3,2,1) in the line (x-1)/1=y/2=(z-1)/1. Then the distance of Q from the line (x-9)/3=(y-9)/2=(z-5)/-2…

Let $\displaystyle \mathrm{Q}(\mathrm{a}, \mathrm{b}, \mathrm{c})$ be the image of the point $\displaystyle \mathrm{P}(3,2,1)$ in the line $\displaystyle \frac{x-1}{1}=\frac{y}{2}=\frac{z-1}{1}$. Then the distance of Q from the line $\displaystyle \frac{x-9}{3}=\frac{y-9}{2}=\frac{z-5}{-2}$ is