Mathematics · 2022
JEE Main · 29 July 2022, Shift 2 · Q14
Let Q be the foot of perpendicular drawn from the point P(1,2,3) to the plane x+2 y+z=14. If R is a point on the plane such that ∠ P R Q=60^°, then…
Let $\displaystyle Q$ be the foot of perpendicular drawn from the point $\displaystyle P(1,2,3)$ to the plane $\displaystyle x+2 y+z=14$. If $\displaystyle R$ is a point on the plane such that $\displaystyle \angle P R Q=60^{\circ}$, then the area of $\displaystyle \triangle P Q R$ is equal to :
Official answer
(2)
$\displaystyle \sqrt{3}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.