Let x_1, x_2, …., x_10 be ten observations such that Σ_i=1^10(x_i-2)=30, Σ_i=1^10(x_i-β)^2=98, β>2, and their variance is 4/5. If μ and σ^2 are…

Let $\displaystyle x_1, x_2, \ldots ., x_{10}$ be ten observations such that $\displaystyle \sum_{i=1}^{10}\left(x_i-2\right)=30, \sum_{i=1}^{10}\left(x_i-\beta\right)^2=98, \beta>2$, and their variance is $\displaystyle \frac{4}{5}$. If $\displaystyle \mu$ and $\displaystyle \sigma^2$ are respectively the mean and the variance of $\displaystyle 2\left(x_1-1\right)+4 \beta$, $\displaystyle 2\left(x_2-1\right)+4 \beta, \ldots ., 2\left(x_{10}-1\right)+4 \beta$, then $\displaystyle \frac{\beta \mu}{\sigma^2}$ is equal to :