Mathematics · 2023
JEE Main · 1 February 2023, Shift 2 · Q77
Let 9=x_1<x_2<…<x_7 be in an A.P. with common difference d. If the standard deviation of x_1, x_2 …, x_7 is 4 and the mean is x̄, then x̄+x_6 is…
Let $\displaystyle 9=x_1<x_2<\ldots<x_7$ be in an A.P. with common difference d . If the standard deviation of $\displaystyle x_1, x_2$ $\displaystyle \ldots, x_7$ is $\displaystyle 4$ and the mean is $\displaystyle \bar{x}$, then $\displaystyle \bar{x}+x_6$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 34$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.