Let f: R → R be defined as: f(x)= {(a-b cos 2 x)/x^2; x<0; x^2+c x+2; 0 ≤ x ≤ 1; 2 x+1; x>1} If f is continuous everywhere in R and m is the number…

Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be defined as : $$f(x)= \begin{cases}\frac{a-b \cos 2 x}{x^2} & ; x<0 \\ x^2+c x+2 & ; 0 \leq x \leq 1 \\ 2 x+1 & ; x>1\end{cases} $$ If $\displaystyle f$ is continuous everywhere in R and m is the number of points where $\displaystyle f$ is NOT differential then $\displaystyle \mathrm{m}+\mathrm{a}+\mathrm{b}+\mathrm{c}$ equals :