Mathematics · 2022
JEE Main · 28 July 2022, Shift 2 · Q88
Let z =a+i b, b ≠ 0 be complex numbers satisfying z^2=z̄ · 2^1-|z|. Then the least value of n ∈ N, such that z^n=(z+1)^n, is equal to \ \ \ \.
Let $\displaystyle \mathrm{z}=a+i b, b \neq 0$ be complex numbers satisfying $\displaystyle z^2=\bar{z} \cdot 2^{1-|z|}$. Then the least value of $\displaystyle \mathrm{n} \in \mathbb{N}$, such that $\displaystyle z^n=(z+1)^n$, is equal to \_\_\_\_.
Official answer
6
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.