Mathematics · 2026
JEE Main · 21 January 2026, Shift 1 · Q24
Let f: R → R be a twice differentiable function such that the quadratic equation f(x) m^2-2 f^′(x) m +f^′ ′(x)=0 in m, has two equal roots for every…
Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be a twice differentiable function such that the quadratic equation $\displaystyle f(x) \mathrm{m}^2-2 f^{\prime}(x) \mathrm{m}+f^{\prime \prime}(x)=0$ in m, has two equal roots for every $\displaystyle x \in \mathbf{R}$. If $\displaystyle f(0)=1, f^{\prime}(0)=2$, and ( $\displaystyle \alpha, \beta$ ) is the largest interval in which the function $\displaystyle f\left(\log _{\mathrm{e}} x-x\right)$ is increasing, then $\displaystyle \alpha+\beta$ is equal to
$\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
1
More from Applications of Derivatives
- Let f(x) be a polynomial of degree 5, and have extrema at x=1 and x=-1. If lim_x → 0((f(x))/x^3)=-5, then f(2)-f(-2) is equal to:2026
- The number of critical points of the function f(x)= {|(sin x)/x|, x ≠ 0; 1, x=0} in the interval (-2 π, 2 π) is equal to:2026
- max_0 ≤ x ≤ π(16 sin (x/2) cos^3(x/2)) is equal to:2026
- Let f: R → R be a differentiable function such that f((x+y)/3)=(f(x)+f(y))/3 for all x, y ∈ R, and f^′(0)=3. Then the minimum value of the function…2026
JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.