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Mathematics · 2022

JEE Main · 29 July 2022, Shift 2 · Q6

Let {a_n}_n=0^∞ be a sequence such that a_0=a_1=0 and a_n+2=3 a_n+1-2 a_n+1, ∀ n ≥ 0. Then a_25 a_23-2 a_25 a_22-2 a_23 a_24+4 a_22 a_24 is equal to

Let $\displaystyle \left\{a_n\right\}_{n=0}^{\infty}$ be a sequence such that $\displaystyle a_0=a_1=0$ and $\displaystyle a_{n+2}=3 a_{n+1}-2 a_n+1, \forall n \geq 0$.Then $\displaystyle a_{25} a_{23}-2 a_{25} a_{22}-2 a_{23} a_{24}+4 a_{22} a_{24}$ is equal to
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.