Mathematics · 2022
JEE Main · 30 July 2022, Shift 2 · Q68
2 Σ_n=2^∞ (n(2 n^2+3))/((n+1)!) is equal to
$\displaystyle 2 \sum_{n=2}^{\infty} \frac{n\left(2 n^2+3\right)}{(n+1)!}$ is equal to
Official answer
(3)
$\displaystyle 2 \mathrm{e}+9$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.