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Mathematics · 2023

JEE Main · 15 April 2023, Shift 1 · Q24

If the sum of the series (1/2-1/3)+(1/2^2-1/(2 · 3)+1/3^2)+(1/2^3-1/(2^2 · 3)+1/(2 · 3^2)-1/3^3)+ (1/2^4-1/(2^3 · 3)+1/(2^2 · 3^2)-1/(2 ·…

If the sum of the series $$\begin{aligned} & \left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{2^2}-\frac{1}{2 \cdot 3}+\frac{1}{3^2}\right)+\left(\frac{1}{2^3}-\frac{1}{2^2 \cdot 3}+\frac{1}{2 \cdot 3^2}-\frac{1}{3^3}\right)+ \\ & \left(\frac{1}{2^4}-\frac{1}{2^3 \cdot 3}+\frac{1}{2^2 \cdot 3^2}-\frac{1}{2 \cdot 3^3}+\frac{1}{3^4}\right)+\ldots \end{aligned} $$ is $\displaystyle \frac{\alpha}{\beta}$, where $\displaystyle \alpha$ and $\displaystyle \beta$ are co-prime, then $\displaystyle \alpha+3 \beta$ is equal to $\displaystyle \_\_\_\_$.
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.