Mathematics · 2019
JEE Main · 9 January 2019, Shift 2 · Q62
Let z_0 be a root of the quadratic equation, x^2+x+1=0. If z=3+6 i z_0^81-3 i z_0^93, then z is equal to:
Let $\displaystyle z_0$ be a root of the quadratic equation, $\displaystyle x^2+x+1=0$. If $\displaystyle z=3+6 i z_0^{81}-3 i z_0^{93}$, then $\displaystyle \arg z$ is equal to :
Official answer
(1)
$\displaystyle \frac{\pi}{4}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.