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Mathematics · 2025

JEE Main · 3 April 2025, Shift 2 · Q3

Let f be a function such that f(x)+3 f(24/x)=4 x, x ≠ 0. Then f(3)+f(8) is equal to

Let $\displaystyle f$ be a function such that $\displaystyle f(x)+3 f\left(\frac{24}{x}\right)=4 x, x \neq 0$. Then $\displaystyle f(3)+f(8)$ is equal to
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.