Mathematics · 2019
JEE Main · 10 January 2019, Shift 1 · Q72
Let f: R → R be a function such that f(x)=x^3+x^2 f^′(1)+x f^′ ′(2)+f^′ ′ ′(3), x ∈ R. Then f(2) equals:
Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be a function such that $\displaystyle f(x)=x^3+x^2 f^{\prime}(1)+x f^{\prime \prime}(2)+f^{\prime \prime \prime}(3), x \in \mathbf{R}$.
Then $\displaystyle f(2)$ equals :
Official answer
(4)
$\displaystyle -2$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.