Mathematics · 2021
JEE Main · 27 July 2021, Shift 1 · Q78
Let f: R → R be a function such that f(2)=4 and f^′(2)=1. Then, the value of lim_x → 2 (x^2 f(2)-4 f(x))/(x-2) is equal to:
Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be a function such that $\displaystyle f(2)=4$ and $\displaystyle f^{\prime}(2)=1$. Then, the value of $\displaystyle \lim _{x \rightarrow 2} \frac{x^2 f(2)-4 f(x)}{x-2}$ is equal to :
Official answer
(3)
$\displaystyle 12$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.