Mathematics · 2019
JEE Main · 12 April 2019, Shift 1 · Q70
Let f: R → R be a continuously differentiable function such that f(2)=6 and f^′(2)=1/48. If ∫_6^f(x) 4 t^3 dt =(x-2) g (x), then lim_x → 2 g(x) is…
Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be a continuously differentiable function such that $\displaystyle f(2)=6$ and
$$f^{\prime}(2)=\frac{1}{48} . \text { If } \int_6^{f(x)} 4 \mathrm{t}^3 \mathrm{dt}=(x-2) \mathrm{g}(x),
$$
then $\displaystyle \lim _{x \rightarrow 2} g(x)$ is equal to:
Official answer
(2)
$\displaystyle 18$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.