Mathematics · 2013
JEE Main · 23 April 2013, Shift 1 · Q90
Let R ={(x, y): x, y ∈ N. and x^2-4 x y.+3 y^2=0}, where N is the set of all natural numbers. Then the relation R is:
Let $\displaystyle \mathrm{R}=\left\{(x, y): x, y \in \mathbf{N}\right.$ and $\displaystyle x^2-4 x y$ $\displaystyle \left.+3 y^2=0\right\}$, where $\displaystyle \mathbf{N}$ is the set of all natural numbers. Then the relation R is :
Official answer
(1)
reflexive but neither symmetric nor
transitive.
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.