Let α=8-14 i, A={z ∈ C: (α z-ᾱ z̄)/(z^2-(z̄)^2-112 i)=1} and B={z ∈ C:|z+3 i|=4}. Then Σ_z ∈ A ∩ B( Re z- Im z) is equal to ____.

Let $\displaystyle \alpha=8-14 i, A=\left\{z \in \mathbb{C}: \frac{\alpha z-\bar{\alpha} \bar{z}}{z^2-(\bar{z})^2-112 i}=1\right\}$ and $\displaystyle B=\{z \in \mathbb{C}:|z+3 i|=4\}$. Then $\displaystyle \sum_{z \in A \cap B}(\operatorname{Re} z-\operatorname{Im} z)$ is equal to $\displaystyle \_\_\_\_$.